KCET 2020 Biology Answer Key – Download KCET Bio Answer Key & Analysis

By Rashmi Kumari Last updated Jul 30, 2020

KCET 2020 Biology Answer Key: Karnataka Exam Authority (KEA) has released the answer key of Biology Paper of KCET 2020. KCET 2020 Biology Answer Key has been released online on the official website of KEA i.e kea.kar.nic.in. KCET 2020 Biology Paper exam was conducted on 30 July 2020 from 10:30 AM to 11:50 AM. Those students who have appeared in KCET Biology Paper exam can check the answer key of KCET Biology Paper from the official website of KEA.

KCET 2020 Biology Answer Key

KEA has finally conducted the Biology Paper exam of KCET 2020 on 30 July 2020. The exam of Biology Paper of KCET 2020 has been concluded at 11:50 AM. The official answer key of KCET 2020 Biology paper exam has been released. Candidates can download KCET 2020 Biology Answer Key set wise A,B,C,D from the official website of KCET 2020.

Click Here to Download KCET 2020 Answer Key PDF

BIOLOGY – CET 2020 – VERSION CODE – D-4 KEYS

Injection of an antidote against snakebite is an example of
1. Auto immunity (B) Innate immunity (C) Active immunity (D) Passive immunity

Ans (D)

Certain tumours are called malignant, because
- they are not neoplastic.
- they are confined to specific locations.
- they invade and damage surrounding tissues.
- they show contact inhibition.

Ans (C)

The transport of which neurotransmitter is interfered by cocaine?
- Dopamine (B) Acetylcholine (C) Serotonin (D) GABA

Ans (A)

In the life, cycle of plasmodium, fertilisation takes place in
- Liver cells (B) Salivary glands of mosquito

Ans (D)

White rust resistant variety of Brassica is
- Pusa Komal (B) Pusa Sadabahar (C) Pusa Swarnim (D) Pusa Shubhra

Ans (C)

Which of the following plant tissues cannot be used as explant in tissue culture?
- Collenchyma (B) Meristem (C) Parenchyma (D) Sclerenchyma

Ans (D)

The hybridisation between naturally incompatible plants like Potato and Tomato can be achieved through
- Mutation breeding (B) Artificial pollination

Ans (C)

A chilly plant was severely infected with Chilly Mosaic Virus (CMV). Identify the technique that helps to raise virus free plants in the next generation from the above virus infected plant.
- Hydroponics (B) Artificial hybridisation

Ans (C)

In sewage treatment, secondary treatment is considered highly significant, because
- it increases the organic content of sewage. (B) it helps to remove debris from the sewage.

Ans (C)

CET2020Biology(D-4)

Ruminant animals can digest cellulose in their food, where as human beings are unable to do so. This is because
1. Methanogens are absent in human gut. (B) Methanogens are present in human gut.

Ans (A)

From the given combinations of steps in PCR, identify the enzyme dependent step/s.
1. Extension only (B) Annealing and extension

Ans (A)

Biolistics method is suitable for gene transfer into
1. Plant cells (B) Viruses (C) Animal cells (D) Bacteria

Ans (A)

Identify the labels M and N in the following Agarose gel electrophoresis representation.

M – Smallest DNA bands, N – Largest DNA bands
- M – Digested DNA bands, N – Undigested DNA bands
- M – Hybridised DNA bands, N – Unhybridised DNA bands
- M – Largest DNA bands, N – Smallest DNA bands

Ans (D)

In RNA interface, the dsRNA molecule prevents
1. aminoacylation
1. transcription of mRNA
1. transport of RNA from nucleus to cytoplasm
1. translation of mRNA

Ans (D)

Now-a-days, the early diagnosis of bacterial or viral infection in humans is possible using
1. CT Scan (B) Serum analyser (C) DNA sequencer (D) PCR

Ans (D)

Which of the following features of plants is not helpful in adapting to desert life?
1. Absence of trichomes on leaf surface (B) Presence of thick cuticle on the leaf surface

Ans (A)

In the following equation of Verhulst-Pearl logistic growth, the letter ‘r’ denotes

dN = rNæ K – N ö

dt ç K ÷

è ø

Population density (B) Extrinsic rate of natural increase

Ans (C)

The shape of the pyramids reflects the growth status of the population. Identify the type of age pyramid represented below for human population.

Declining (B) Ascending (C) Expanding (D) Stable

Ans (A)

Identify the possible link ‘M’ in the following food chain:

Plant ® Insect ® ®Snake ® Eagle

Ichthyophis (B) Rabbit (C) Wolf (D) Frog

Ans (D)

The organisms which invade a bare area to initiate an ecological succession are known as
- Pioneer species (B) Key stone species

Ans (A)

Which one of the following is not included under in-situ conservation?
- Biosphere Reserve (B) National Park

Ans (D)

Which one of the following is a wrong statement?
- Ozone in upper part of the atmosphere is harmful to animals.
- Most of the forests have been lost in tropical areas.
- Green house effect is a natural phenomenon.
- Eutrophication is a natural phenomenon in fresh water lakes.

Ans (A)

According to Supreme Court of India, ruling with respect to ‘Bharat Stage VI’ Norms, from which date, these are supposed to be implemented in the country?
- 10^th December, 2020 (B) 1^st April, 2020

Ans (B)

CET2020Biology(D-4)

Match the following classes of Fungi (Column-I) with the examples (Column-II).

Column I	Column II
(1)	Phycomycetes	(p)	Penicillium
(2)	Ascomycetes	(q)	Alternaria
(3)	Basidiomycetes	(r)	Albugo
(4)	Deuteromycetes	(s)	Puccinia

Choose the correct option:

(A) (1) – (r), (2) – (p), (3) – (s), (4) – (q) (B) (1) – (p), (2) – (s), (3) – (r), (4) – (q)

Ans (A)

Observe the following simplified scheme and choose the correct option that matches with the letters given in the boxes.

p – Agnatha, q – Gnathostomata, r – Tetrapoda, s – Pisces
- p – Agnatha, q – Gnathostomata, r – Pisces, s – Tetrapoda
- p – Gnathostomata, q – Agnatha, r – Tetrapoda, s – Pisces
- p – Tetrapoda, q – Pisces, r – Gnathostomata, s – Agnatha

Ans (B)

Identify the floral unit ‘I’ in the given floral diagram.

Perianth (B) Sepal (C) Petal (D) Tepal

Ans (A)

A student observes grass and Hibiscus plants in his garden during noon. To his surprise, only the leaves of grass were found rolled inwards. The reason could be
- due to higher rate of transpiration.
- presence of more number of stomata on the grass leaves.
- undifferentiated mesophyll in grass leaves.
- presence of Bulliform cells in the grass leaves.

Ans (D)

CET2020Biology(D-4)

In the below diagram, identify the part which connects the peripheral microtubules to the central sheath.

Radial spoke (B) Plasma membrane

Ans (A)

The element whose percentage weight is highest in both earth’s crust and human body is
- Calcium (B) Hydrogen (C) Carbon (D) Oxygen

Ans (D)

Identify the event in meiosis mediated by the enzyme recombinase.
- Interkinesis (B) Synaptic pairing (C) Terminalization (D) Crossing Over

Ans (D)

The deficiency of which of these elements interrupts photolysis of water during photosynthesis?
- N and P (B) Mn and Cl (C) Zn and Cu (D) Ca and K

Ans (B)

In C₄ plants, C₃ cycle takes place in
- Bundle sheath cells (B) Mesophyll cells

Ans (A)

During Citric Acid cycle, the various organic acid undergo decarboxylation. Which of the following organic acids of the above cycle have 4C, 5C and 6C respectively?
- Pyruvic acid, a-Ketogluetaric acid and Cirtic acid
- Oxaloacetic acid, Citric acid and Succinic acid
- Succinic acid, a-Ketoglutaric acid and citric acid.
- Pyruvic acid, Malic acid and a-Ketoglutaric acid.

Ans (C)

CET2020Biology(D-4)

Consider the following statements regarding photosynthesis and respiration in plants and select the correct option.
RuBisCO has high affinity to oxygen in low CO₂ concentration.
The Calvin pathway occurs in the chloroplast of bundle sheath cells of C₄ plants.
Yeast poison themselves when the concentration of alcohol reaches 7%.
Oxygen is a final hydrogen acceptor during aerobic respiration.
Statements I & IV are correct, III is wrong.
Statements II & IV are correct, I is wrong.
Statements I & II are correct, IV is wrong.
Statements I & III are correct, II is wrong.

Ans (A)

Column I Column II (1) Pancreas (p) Pepsin (2) Gastric glands (q) Enterokinase (3) Small intestine (r) Ptyalin (4) Salivary glands (s) Trypsin

Match the digestive glands given in Column-I with their respective enzymes given in Column-II and choose the correct combination from the given options.

Choose the correct option:

(A) (1) – (q), (2) – (s), (3) – (r), (4) – (p) (B) (l) – (p), (2) – (q), (3) – (r), (4) – (s)

Ans (C)

Column I Column II (1) Neutrophils (p) 6 – 8% (2) Lymphocytes (q) 60 – 65% (3) Monocytes (r) 0.5 – 1% (4) Basophils (s) 2 – 3% (5) Eosinophils (t) 20 – 25%

Match the different types of Leucocytes (Column-I) with their percentage of occurrence (Column-II) in a healthy adult human and choose the correct answer.

Choose the correct option:

(A) (1) – (q), (2) – (t), (3) (p), (4) – (r), (5) – (s)

(B) (1) – (q), (2) – (r), (3) – (s), (4) – (t), (5) – (p)

(D) (1) – (q), (2) – (t), (3) – (r), (4) – (s), (5) – (p)

Ans (A)

In which part of the human brain corpora quadrigemina is located?
- Cerebral hemisphere (B) Forebrain

Ans (D)

CET2020Biology(D-4)

A girl after attaining sexual maturity shows development of growing ovarian follicles, development of mammary glands and high pitch of voice. These changes are attributed to hormones.
- Androgens (B) Melatonin (C) Estrogens (D) Progesterone

Ans (C)

In apple, the chromosome number of gametes is 17. What is the chromosome number in its Primary Endosperm Nucleus (PEN)?

(A) 51 (B) 34 (C) 68 (D) 17

Ans (A)

Identify the vegetative propagule ‘M’ in the following diagram:

Runner (B) Bulbil (C) Offset (D) Rhizome

Ans (C)

During an excavation of soil, Pollen fossils were retrieved from deepest layer of soil. The pollen grains remained as fossils because
- Pollen grains are asexual reproductive structures.
- The intine of pollen grains is made up of pectin.
- Exine has spiny Ornamentation.
- The exine of pollen grains is highly resistant to enzyme action.

Ans (D)

Identify the mismatch.
- Primary Endosperm Nucleus – Triploid (B) Antipodals – Haploid

Ans (D)

Identify the correct order of events in pollen-pistil interaction from the options given below:
Release of male gametes into the embryo sac.
Deposition of pollen grains on stigma.
Entry of pollen tube into embryo sac.
Development of pollen tube
Entry of pollen tube into the ovule.

(A) V ® IV ® III ® II ® I (B) IV ® III ® II ® I ® V

Ans (C)

CET2020Biology(D-4)

Match the months listed in Column-I with the organogenesis of foetus in Column-II.

Column – I	Column – II
(i)	First month	(a)	Separation of eye lids
(ii)	Second month	(b)	Hairs on head
(iii)	Fifth month	(c)	Heart
(iv)	Six month	(d)	Limbs and digits

	(i)	(ii)	(iii)	(iv)
(A)	(c)	(d)	(b)	(a)
(B)	(c)	(d)	(a)	(b)
(C)	(b)	(c)	(d)	(a)
(D)	(d)	(b)	(c)	(a)

Ans (A)

When the fallopian tube is blocked at ampullary region, the ovum fails to move from
- Infundibulum to Isthmus (B) Isthmus to infundibulum

Ans (A)

Identify the cells represented as p, q, r and s in the schematic representation of Oogenesis, shown below and choose the correct option.

p – Oogonia, q – Primary oocyte, r – Secondary oocyte, s – Ovum
- p – Ovum, q – Oogonia, r – Primary oocyte, s – Secondary oocyte
- p – Secondary oocyte, q – Primary oocyte, r – Ovum, s – Oogonia
- p – Ovum, q – Secondary oocyte, r – Primary oocyte, s – Ovum

Ans (A)

Which of the following contraceptives could be effective in avoiding pregnancy if used within 72 hours after casual unprotected intercourse?
- Progestogen – Estrogen combination (B) Androgen – FSH combination

Ans (A)

Choose the correct statement regarding the GIFT (Gamete Intrafallopian Tube Transfer) procedure.
- Ova are collected from a female donor and are transferred to the uterus of recipient.
- Ova collected from a female donor are transferred to the fallopian tube to facilitate zygote formation in the recipient.
- Zygote is collected from female donor and transferred to the fallopian tube of recipient.
- Zygote is collected from a female donor and transferred to the uterus of recipient.

Ans (B)

CET2020Biology(D-4)

Which of the following characters was not studied by Mendel in his Pea plant experiments?
- Leaf shape (B) Stem height (C) Pod shape (D) Seed shape

Ans (A)

In an Organism, mutation in a single gene exhibits multiple phenotypic expressions. Identify the underlying genetic mechanism in the above instance.
- Multiple allelism (B) Pleiotropy

Ans (B)

A pure breeding pea plant with round yellow seeds was crossed with pea plant having wrinkled green seeds. On selfing of F₁ hybrid of his cross, 64 progenies were obtained in F₂ generation. Find out the number of F₂ progenies showing non-parental characters.

(A) 24 (B) 36 (C) 4 (D) 12

Ans (A)

A man with blood group A marries a woman having blood group B. The maximum possible blood groups among their progenies are
- A, B, AB, O (B) AB only (C) A, B, AB (D) A, B

Ans (A)

The length of DNA helix in a typical nucleosome is

(A) 6.6 ´ 10⁹ bp (B) 200 bp (C) 1000 bp (D) 3.2 ´ 10⁶ bp

Ans (B)

Which of the following types of RNA carries amino acids towards ribosome during translation?
- mRNA (B) rRNA (C) dsRNA (D) tRNA

Ans (D)

In eukaryotes, the entire base sequence of a gene do not appear in mature RNA because
- some gene sequences are removed by exonuclease.
- transcription in eukaryotes consumes more energy.
- coding sequences are removed during processing.
- introns are removed during processing.

Ans (D)

Suppose DNA samples collected for DNA fingerprinting analysis are less than the required quantity. Which of the following techniques is helpful to make the samples sufficient for above analysis?
- DNA probing (B) Electrophoresis

Ans (D)

When Escherichia coli cells are cultured in a medium where Lactose is absent, the ‘i’ gene of

Lac Operon continues to produce repressor mRNA, because it is

a structural gene. (B) a non-coding gene.

Ans (D)

CET2020Biology(D-4)

For the given sequence of DNA, identify the complementary sequence of bases on its mRNA from the options given below:

DNA 3¢ – ATGCATGCATGC – 5¢

5¢ – GCATGCATGCAT – 3¢ (B) 5¢ – UACGUACGUACG –3¢

Ans (B)

Which among the following was the biggest land dinosaur?
- Triceratops (B) Stegosaurus

Ans (C)

In a population of plants, some were extremely tall and the remaining were extremely dwarf. No plants of the population showed intermediate height. The type of operation of natural selection in the above case is
- Disruptive (B) Balancing

Ans (A)

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