KCET 2020 Biology Answer Key: Karnataka Exam Authority (KEA) has released the answer key of Biology Paper of KCET 2020. KCET 2020 Biology Answer Key has been released online on the official website of KEA i.e kea.kar.nic.in. KCET 2020 Biology Paper exam was conducted on 30 July 2020 from 10:30 AM to 11:50 AM. Those students who have appeared in KCET Biology Paper exam can check the answer key of KCET Biology Paper from the official website of KEA.
KCET 2020 Biology Answer Key
KEA has finally conducted the Biology Paper exam of KCET 2020 on 30 July 2020. The exam of Biology Paper of KCET 2020 has been concluded at 11:50 AM. The official answer key of KCET 2020 Biology paper exam has been released. Candidates can download KCET 2020 Biology Answer Key set wise A,B,C,D from the official website of KCET 2020.
BIOLOGY – CET 2020 – VERSION CODE – D-4 KEYS
- Injection of an antidote against snakebite is an example of
- Auto immunity (B) Innate immunity (C) Active immunity (D) Passive immunity
- Certain tumours are called malignant, because
- they are not neoplastic.
- they are confined to specific locations.
- they invade and damage surrounding tissues.
- they show contact inhibition.
- The transport of which neurotransmitter is interfered by cocaine?
- Dopamine (B) Acetylcholine (C) Serotonin (D) GABA
- In the life, cycle of plasmodium, fertilisation takes place in
- Liver cells (B) Salivary glands of mosquito
(C) RBCs of humans (D) Stomach of mosquito
- White rust resistant variety of Brassica is
- Pusa Komal (B) Pusa Sadabahar (C) Pusa Swarnim (D) Pusa Shubhra
- Which of the following plant tissues cannot be used as explant in tissue culture?
- Collenchyma (B) Meristem (C) Parenchyma (D) Sclerenchyma
- The hybridisation between naturally incompatible plants like Potato and Tomato can be achieved through
- Mutation breeding (B) Artificial pollination
(C) Somatic hybridisation (D) Conventional breeding
- A chilly plant was severely infected with Chilly Mosaic Virus (CMV). Identify the technique that helps to raise virus free plants in the next generation from the above virus infected plant.
- Hydroponics (B) Artificial hybridisation
(C) Meristem culture (D) Self pollination
- In sewage treatment, secondary treatment is considered highly significant, because
- it increases the organic content of sewage. (B) it helps to remove debris from the sewage.
(C) it reduces the BOD level of sewage. (D) it helps in the production of biogas.
- Ruminant animals can digest cellulose in their food, where as human beings are unable to do so. This is because
- Methanogens are absent in human gut. (B) Methanogens are present in human gut.
(C) Cellulose is a complex sugar. (D) Cellulose reduces the bulk of food.
- From the given combinations of steps in PCR, identify the enzyme dependent step/s.
- Extension only (B) Annealing and extension
(C) Annealing and denaturation (D) Denaturation and extension
- Biolistics method is suitable for gene transfer into
- Plant cells (B) Viruses (C) Animal cells (D) Bacteria
- Identify the labels M and N in the following Agarose gel electrophoresis representation.
- M – Smallest DNA bands, N – Largest DNA bands
- M – Digested DNA bands, N – Undigested DNA bands
- M – Hybridised DNA bands, N – Unhybridised DNA bands
- M – Largest DNA bands, N – Smallest DNA bands
- In RNA interface, the dsRNA molecule prevents
- transcription of mRNA
- transport of RNA from nucleus to cytoplasm
- translation of mRNA
- Now-a-days, the early diagnosis of bacterial or viral infection in humans is possible using
- CT Scan (B) Serum analyser (C) DNA sequencer (D) PCR
- Which of the following features of plants is not helpful in adapting to desert life?
- Absence of trichomes on leaf surface (B) Presence of thick cuticle on the leaf surface
(C) Leaves modified into spines (D) Presence of sunken stomata
- In the following equation of Verhulst-Pearl logistic growth, the letter ‘r’ denotes
dN = rNæ K – N ö
dt ç K ÷
- Population density (B) Extrinsic rate of natural increase
(C) Intrinsic rate of natural increase (D) Carrying capacity
The shape of the pyramids reflects the growth status of the population. Identify the type of age pyramid represented below for human population.
- Declining (B) Ascending (C) Expanding (D) Stable
- Identify the possible link ‘M’ in the following food chain:
Plant ® Insect ® ®Snake ® Eagle
- Ichthyophis (B) Rabbit (C) Wolf (D) Frog
- The organisms which invade a bare area to initiate an ecological succession are known as
- Pioneer species (B) Key stone species
(C) Climatic species (D) Endemic species
- Which one of the following is not included under in-situ conservation?
- Biosphere Reserve (B) National Park
(C) Sanctuary (D) Botanical Garden
- Which one of the following is a wrong statement?
- Ozone in upper part of the atmosphere is harmful to animals.
- Most of the forests have been lost in tropical areas.
- Green house effect is a natural phenomenon.
- Eutrophication is a natural phenomenon in fresh water lakes.
- According to Supreme Court of India, ruling with respect to ‘Bharat Stage VI’ Norms, from which date, these are supposed to be implemented in the country?
- 10th December, 2020 (B) 1st April, 2020
(C) 1st June, 2021 (D) 1st January, 2021
- Match the following classes of Fungi (Column-I) with the examples (Column-II).
|Column I||Column II|
Choose the correct option:
(A) (1) – (r), (2) – (p), (3) – (s), (4) – (q) (B) (1) – (p), (2) – (s), (3) – (r), (4) – (q)
(C) (1) – (q), (2) – (p), (3) – (s), (4) – (r) (D) (1) – (r), (2) – (p), (3) – (q), (4) – (s)
- Observe the following simplified scheme and choose the correct option that matches with the letters given in the boxes.
- p – Agnatha, q – Gnathostomata, r – Tetrapoda, s – Pisces
- p – Agnatha, q – Gnathostomata, r – Pisces, s – Tetrapoda
- p – Gnathostomata, q – Agnatha, r – Tetrapoda, s – Pisces
- p – Tetrapoda, q – Pisces, r – Gnathostomata, s – Agnatha
- Identify the floral unit ‘I’ in the given floral diagram.
- Perianth (B) Sepal (C) Petal (D) Tepal
- A student observes grass and Hibiscus plants in his garden during noon. To his surprise, only the leaves of grass were found rolled inwards. The reason could be
- due to higher rate of transpiration.
- presence of more number of stomata on the grass leaves.
- undifferentiated mesophyll in grass leaves.
- presence of Bulliform cells in the grass leaves.
- In the below diagram, identify the part which connects the peripheral microtubules to the central sheath.
- Radial spoke (B) Plasma membrane
(C) Interdoublet bridge (D) Central microtubule
- The element whose percentage weight is highest in both earth’s crust and human body is
- Calcium (B) Hydrogen (C) Carbon (D) Oxygen
- Identify the event in meiosis mediated by the enzyme recombinase.
- Interkinesis (B) Synaptic pairing (C) Terminalization (D) Crossing Over
- The deficiency of which of these elements interrupts photolysis of water during photosynthesis?
- N and P (B) Mn and Cl (C) Zn and Cu (D) Ca and K
- In C4 plants, C3 cycle takes place in
- Bundle sheath cells (B) Mesophyll cells
(C) Bulliform cells (D) Companion cells
- During Citric Acid cycle, the various organic acid undergo decarboxylation. Which of the following organic acids of the above cycle have 4C, 5C and 6C respectively?
- Pyruvic acid, a-Ketogluetaric acid and Cirtic acid
- Oxaloacetic acid, Citric acid and Succinic acid
- Succinic acid, a-Ketoglutaric acid and citric acid.
- Pyruvic acid, Malic acid and a-Ketoglutaric acid.
- Consider the following statements regarding photosynthesis and respiration in plants and select the correct option.
- RuBisCO has high affinity to oxygen in low CO2 concentration.
- The Calvin pathway occurs in the chloroplast of bundle sheath cells of C4 plants.
- Yeast poison themselves when the concentration of alcohol reaches 7%.
- Oxygen is a final hydrogen acceptor during aerobic respiration.
- Statements I & IV are correct, III is wrong.
- Statements II & IV are correct, I is wrong.
- Statements I & II are correct, IV is wrong.
- Statements I & III are correct, II is wrong.
|Column I Column II (1) Pancreas (p) Pepsin (2) Gastric glands (q) Enterokinase (3) Small intestine (r) Ptyalin (4) Salivary glands (s) Trypsin|
Match the digestive glands given in Column-I with their respective enzymes given in Column-II and choose the correct combination from the given options.
Choose the correct option:
(A) (1) – (q), (2) – (s), (3) – (r), (4) – (p) (B) (l) – (p), (2) – (q), (3) – (r), (4) – (s)
(C) (1) – (s), (2) – (p), (3) – (q), (4) – (r) (D) (1) – (r), (2) – (q), (3) – (p), (4) – (s)
|Column I Column II (1) Neutrophils (p) 6 – 8% (2) Lymphocytes (q) 60 – 65% (3) Monocytes (r) 0.5 – 1% (4) Basophils (s) 2 – 3% (5) Eosinophils (t) 20 – 25%|
Match the different types of Leucocytes (Column-I) with their percentage of occurrence (Column-II) in a healthy adult human and choose the correct answer.
Choose the correct option:
(A) (1) – (q), (2) – (t), (3) (p), (4) – (r), (5) – (s)
(B) (1) – (q), (2) – (r), (3) – (s), (4) – (t), (5) – (p)
(C) (1) – (r), (2) – (s), (3) – (t), (4) – (q), (5) – (p)
(D) (1) – (q), (2) – (t), (3) – (r), (4) – (s), (5) – (p)
- In which part of the human brain corpora quadrigemina is located?
- Cerebral hemisphere (B) Forebrain
(C) Hindbrain (D) Midbrain
- A girl after attaining sexual maturity shows development of growing ovarian follicles, development of mammary glands and high pitch of voice. These changes are attributed to hormones.
- Androgens (B) Melatonin (C) Estrogens (D) Progesterone
- In apple, the chromosome number of gametes is 17. What is the chromosome number in its Primary Endosperm Nucleus (PEN)?
(A) 51 (B) 34 (C) 68 (D) 17
- Identify the vegetative propagule ‘M’ in the following diagram:
- Runner (B) Bulbil (C) Offset (D) Rhizome
- During an excavation of soil, Pollen fossils were retrieved from deepest layer of soil. The pollen grains remained as fossils because
- Pollen grains are asexual reproductive structures.
- The intine of pollen grains is made up of pectin.
- Exine has spiny Ornamentation.
- The exine of pollen grains is highly resistant to enzyme action.
- Identify the mismatch.
- Primary Endosperm Nucleus – Triploid (B) Antipodals – Haploid
(C) Zygote – Diploid (D) Synergids – Diploid
- Identify the correct order of events in pollen-pistil interaction from the options given below:
- Release of male gametes into the embryo sac.
- Deposition of pollen grains on stigma.
- Entry of pollen tube into embryo sac.
- Development of pollen tube
- Entry of pollen tube into the ovule.
(A) V ® IV ® III ® II ® I (B) IV ® III ® II ® I ® V
(C) II ® IV ® V ® III ® I (D) II ® IV ® III ® V® I
- Match the months listed in Column-I with the organogenesis of foetus in Column-II.
|Column – I||Column – II|
|(i)||First month||(a)||Separation of eye lids|
|(ii)||Second month||(b)||Hairs on head|
|(iv)||Six month||(d)||Limbs and digits|
- When the fallopian tube is blocked at ampullary region, the ovum fails to move from
- Infundibulum to Isthmus (B) Isthmus to infundibulum
(C) Ovary to ampulla (D) Isthmus to Uterus
- Identify the cells represented as p, q, r and s in the schematic representation of Oogenesis, shown below and choose the correct option.
- p – Oogonia, q – Primary oocyte, r – Secondary oocyte, s – Ovum
- p – Ovum, q – Oogonia, r – Primary oocyte, s – Secondary oocyte
- p – Secondary oocyte, q – Primary oocyte, r – Ovum, s – Oogonia
- p – Ovum, q – Secondary oocyte, r – Primary oocyte, s – Ovum
- Which of the following contraceptives could be effective in avoiding pregnancy if used within 72 hours after casual unprotected intercourse?
- Progestogen – Estrogen combination (B) Androgen – FSH combination
(C) Testosterone – Relaxin combination (D) Relaxin – Oxytocin combination
- Choose the correct statement regarding the GIFT (Gamete Intrafallopian Tube Transfer) procedure.
- Ova are collected from a female donor and are transferred to the uterus of recipient.
- Ova collected from a female donor are transferred to the fallopian tube to facilitate zygote formation in the recipient.
- Zygote is collected from female donor and transferred to the fallopian tube of recipient.
- Zygote is collected from a female donor and transferred to the uterus of recipient.
- Which of the following characters was not studied by Mendel in his Pea plant experiments?
- Leaf shape (B) Stem height (C) Pod shape (D) Seed shape
- In an Organism, mutation in a single gene exhibits multiple phenotypic expressions. Identify the underlying genetic mechanism in the above instance.
- Multiple allelism (B) Pleiotropy
(C) Incomplete dominance (D) Polygenic inheritance
- A pure breeding pea plant with round yellow seeds was crossed with pea plant having wrinkled green seeds. On selfing of F1 hybrid of his cross, 64 progenies were obtained in F2 generation. Find out the number of F2 progenies showing non-parental characters.
(A) 24 (B) 36 (C) 4 (D) 12
- A man with blood group A marries a woman having blood group B. The maximum possible blood groups among their progenies are
- A, B, AB, O (B) AB only (C) A, B, AB (D) A, B
- The length of DNA helix in a typical nucleosome is
(A) 6.6 ´ 109 bp (B) 200 bp (C) 1000 bp (D) 3.2 ´ 106 bp
- Which of the following types of RNA carries amino acids towards ribosome during translation?
- mRNA (B) rRNA (C) dsRNA (D) tRNA
- In eukaryotes, the entire base sequence of a gene do not appear in mature RNA because
- some gene sequences are removed by exonuclease.
- transcription in eukaryotes consumes more energy.
- coding sequences are removed during processing.
- introns are removed during processing.
- Suppose DNA samples collected for DNA fingerprinting analysis are less than the required quantity. Which of the following techniques is helpful to make the samples sufficient for above analysis?
- DNA probing (B) Electrophoresis
(C) Chromatography (D) PCR
- When Escherichia coli cells are cultured in a medium where Lactose is absent, the ‘i’ gene of
Lac Operon continues to produce repressor mRNA, because it is
- a structural gene. (B) a non-coding gene.
(C) an operator gene. (D) a constitutive gene.
- For the given sequence of DNA, identify the complementary sequence of bases on its mRNA from the options given below:
DNA 3¢ – ATGCATGCATGC – 5¢
- 5¢ – GCATGCATGCAT – 3¢ (B) 5¢ – UACGUACGUACG –3¢
(C) 5¢ – TACGTACGTACG – 3¢ (D) 3¢ – UACGUACGUACG –5¢
- Which among the following was the biggest land dinosaur?
- Triceratops (B) Stegosaurus
(C) Tyrannosaurus rex (D) Brachiosaurus
- In a population of plants, some were extremely tall and the remaining were extremely dwarf. No plants of the population showed intermediate height. The type of operation of natural selection in the above case is
- Disruptive (B) Balancing
(C) Directional (D) Stabilizing
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